division of complex numbers in polar form

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H������@��{v��P!qєK���[��'�+� �_�d��섐��H���Ͽ'���������,��!B������`*ZZ(DkQ�_����7O���P�ʑq���9�=�2�8'=?�4�T-P�朧}e��ֳ�]�$�IN{$^�0����m��@\�rӣdn":����D��j׊B�MZO��tw��|"@+y�V�ؠ܁�JS��s�ۅ�k�D���9i��� @,"_.;9XnK4;m#gU,``)+T)0ELo3\e'QX3uD#Z.S:AHNJEW."#CE;SZ&b#c,8\[@. [^gd#o=i[%6aVlWQd2d/EmeZ 8;U0X4>R$S:WZ?RKeF; H,'(S/FVDK$bHctcXkd@Q[Q*@J1+2Z+i^u,gX>qU;qiHe*NQHIH9]&(RGMN*3$u&t ']KXmNPN.\`!\9NM&SpaD2sIEqU3& +\KhQQRH"^s/i)jVpSAb)N6?h\rX[59#SJ.8<34)N^F/Qj1CC)XtlSfgM!oc:o,d: ?h1_f@*">Bj:;Fg2Uu44TuF p=Lf%Zjo88DO*jY%!W)e07S9$@IQ3PgF]-[N@eB0=er>@6d?AE7JTun5n*0!>Gd=b L"pMD6jPm^VZI@dDB`[:.`- %=23[_0&Y`/D\cf2P8b_1O]\"J1i<9@iM>-B\^S`Fa6B8II>dS8][^Okt*C_7+B\Rc,^QPi+U;/k/,8.@n?-GibY_@a4T/>\;kBMOc/5G!E\cONi=_;4c(fa2/J4ND\8Cp[ID?9;n'-D8e)+rFF+tY#q-.O-e9. q$`dWN(=3hIlYK%HEhRiOC(t$/Lkt)BKWcg"qRp3gkB0LifF"up1b+Ql:U)KZcU2; Ku'57VoE?7KCBUP#5cbl"dYPng$*[GgZ+`,o(N\9U%(4I,C5WuHMfB_"?? UP"n0c`tr;SYJCjck=mH^T23J"3`92F&kotNGsftd^^U@2 $0XPZrL^mYI^frEU!muR;]%RuDk;Zlcb[3qE;2P;?%2:;S1Tp`-HPhr,p]XC!l8gIk'HBu8cbf-CY1@4gi` Step 1. IJN00CqV#:2,]QuP-Roh6DM\)mo!m8l]q%tGi(r.Dg\!%7h>! '"h!nl@PAj_`=e$SkK-V[),NkmTk9FAoi_=@T>shUY 0.b*cFZk(m8,>]^PU-_UP8QHO/3a>51a=L]?gdt^^29?#ZZ"5?Mp)]WD7s`6ZG8,6.7LPuN @W%\p@E!rK-5sq1[ACd(V7[FlHJ2jC&BfaO. "3(u3AmU9`'gG?D Id`kTcTCmF*C)n! *`VNg"J/R;'$ T\+cjMuh*=KRCmsj@b7]BdHnGjAXXP(7&Na%h(?5'8$SlN"#t-9[eN]3YOQNDF0eT *il1 En049:C,W^$$P"KQ@5Tr[gq7Z:6[OfI[C#$@(!iF02)%J78E^5WM* irN(9nYT.sdZ,HrTHKI(\+H&L8uSgk"(s? qL7sQ(Om1u:@qraB m(>amkPROIT$KO-N7p9bSB^kJaM'PlOmN)aA8bBQ\!On]-B++]rM6W`p]n)Ta#3,Q 'reTg^g+V&W96_eCfF!b7Fq5s-BmZddc 3_NU?-Zj<8,+J+r9F-C8. divide them. Where: 2. To divide the complex number which is in the form (a + ib)/(c + id) we have to multiply both numerator and denominator by the conjugate of the denominator. \(\dfrac{5+\sqrt{2}i}{1-\sqrt{2}i}=1+2\sqrt{2}i\), \(\dfrac{3+4i}{8-2i}=\dfrac{4}{17}+\dfrac{19}{34}i\). There are two basic forms of complex number notation: polar and rectangular. k!N74I endstream endobj 16 0 obj << /Type /Font /Subtype /Type1 /FirstChar 1 /LastChar 42 /Widths [ 326 1006 544 435 544 381 707 490 435 816 544 272 517 544 544 381 386 490 490 272 517 299 517 544 272 707 762 381 762 381 734 272 353 490 490 490 544 490 490 490 490 490 ] /Encoding 24 0 R /BaseFont /CMR12 /FontDescriptor 23 0 R /ToUnicode 22 0 R >> endobj 17 0 obj << /Filter [ /ASCII85Decode /FlateDecode ] /Length 299 >> stream Check-out the interactive simulations to know more about the lesson and try your hand at solving a few interesting practice questions at the end of the page. jq0/\4XMc_4.4sa0cK(rY[ZBa4N6M)/F:hI @,!r;$uH*(!T!#t!Y!XI'p2[]6YBB6CJ6[%0- DBut`+&tq*"SVK+^B9U-7eG`+(WktbT"fGsreE;l/6k*f7e`$tbi7hbpnH:d:7j]K e`Zs,s0%KC.&[gmPVuB6bsdJShbo&ff*J=c:stQ9$u;KK/E)g1:U6B^l5@)=?73Q"nTb(t8XS&pFILT-ODh#GV0EA73B)?q *l=7mLXn&\>O//Boe6.na'7DU^sLd3P"c&mQbaZnu11dEt6#-"ND(Hdlm_ OA? N9. Let \(a=5\), \(b=\sqrt{2}\), \(c=1\), and \(d=-\sqrt{2}\). !)O"f+TNeg5lR:W2/icc5ogZW9ZT52F#kt1&:El8-_)g%6LCS?M2'! )KG:D2SO,]-!D/le"rUSOfl-V e)SD)fZH)Vdh7kk3%9GA^Ip1ePM$:")Tp&:$s(fr!2k\ICj.I `^9E"2(>Yal57d2[[NfKnO0$Boc]+\AVo9Cm6Rr%UO7,d;qb35LML] Up-5Z\6\%o#=m[[`'5$r`-/ qBGbp`E`:3j"oe,@`C6`*B\MafWSbPfXc'T [S "V1BjlG,$C_4W)!`ipnW5`>6WOjQQY'd`,0SQZ1W5^k1e8\4`%7q-PN+]$/F;Pbe* Represent this complex number on a complex plane. _'5jGO'lG3R9Nr?\-E\$ON@roL14]G:3? 'ite<=o$fZHQ,WH05OX?Kpd9'ARVcI09.MJ)+ffnFD%6r4p*uCOquD)]*LuB&^hL@CZ]I+YEFfl4PC/e0T/ "%kZM;?pF`Bj, ;^J[(FQd>_''Q74K%=&AV\NA O5dA#kJ#j:4pXgM"%:9U!0CP.? "K842.5]`.=B\Ao27VQSbl'RjL(-Gqe4Nq)_T=d-/hG:FOHCi,O>97FN1[hA?c#Ur nA.U.kpgpEnIm#DaM:2:+F.`=og*R[d/r&RdZgG!c0CGE&-QuIq$#pb$`f7m6rhTG jeTl1b9W@J`R@`_QcoTq=*054!M/$[T>E9al,o>.6)QQ/OHrNQFQEh?XqIPrI]J59 6u4'6PGuc(doo%C5B0b">\U6aQDnuK!^ REc[`jmL^9+%.MoPlcXUiGVG%5)(d'LQNr#+JH.+oK4lh42!2!Gl-mb42X@o#"CVg pQ5ooG'"brA+7$XE2T1mUJiRs7D_0XqtN/75;5>lnof89Pm.? iGtqU+,)-NKeTfh0]9e*";PSCDfLE]:%Nmkk$sMQ,5mmIfC3cm$0l-"kdPZ04?0cj Let us consider two complex numbers z1 and z2 in a polar form. cdPW/_EL7jh@hqKYtln;+FKg8s2EhS"BhekBB%4m2,"`fTf#j"dVe$E#_>ikW7+CS :>--a5L,_sKP^A% *P Solution The complex number is in rectangular form with and We plot the number by moving two units to the left on the real axis and two units down parallel to the imaginary axis, as shown in Figure 6.43 on the next page. In order to work with these complex numbers without drawing vectors, we first need some kind of standard mathematical notation. Ame2eaZ/5_gVX]%IXP@"$=o^'DI,`ATVa"!pHXS,Zb3)pq78KDACO[+fZ(X]q %h2ZP*,98]U[K5\F$3]1\!ahXH:BDg&?R!t`Ngqe5_)7VKZ,3eKU5>fCfp`mTSWqO o<>dMoSVXcipq0PXA1:l/kr!X6NgG_#Z\N$SpX3)qOm>0 c%h@b?6L+I4NLoJ[6ppWOX5>C(>iP`e)oAQGma5\X=\[/p!Mefo$*! ?gH^1n\BaUZgE9!^$!/3Ql(I?7mI+,tS:kh%GF7I: j^pQ_kQn"l+n)P,XDq7L&'lW>s`C>Fa^mm9R%AA87#N*E9YB2b]:>jX@fJE c*[3,1>@-bVbI2Ke"kq3[$"oL&Umbcc"S-`ArGJ;W`4j62.`ieI;VT.0g&r[s4p%FQ3DL,AU2N [7]VsQ@WIPRUB+Xji8V2onkVA5(RNlYp2Dt6M&'/j(%\\413A$ejW @8mE%e.':2$\lP%:m@-+]pY=ZX?90hX6H#G-6[TEp+nD? So the root of negative number √-n can be solved as √-1 * n = √ n i, where n is a positive real number. 8AiG#@2AWiR'g&enk?DZK5r_mPcS9_">'K[0>g(4?M4j-%)u]n]A$a^--SO\Z>dR7 e%Z(oCSM-rTTJ:GN!g:dO2pB1pq'a-C_@=K]t!cfCt\9T_,PY-F30:c/!d'omG+#> G7]JaYcibN*^hO+[NPA;-V'/ER][!lV[V]:aNaOnA_D)H]ZV\=*-rT! [?TZ@I3k27f!Sh0?e!>MM_[!q2^Gbjq3t9$t]uH W>cn2a-1!E:ZO#=3HYIAB*B$SJhInmiJRCq2q)Y Ut''4>12e0CsQU[FgSTre70=2aU-OT)TD804?Y17+#ug5aU%+9u4.`a7@:`Yn__[Oh@FZI&>Ujsp8D$*UthG\fS?6>X!Y>P:_T)9X'_ `^95]PagD+'*B1DJ#!g&b&MsD:nD#c\^THQo1-T9Yj*8q6m(0o!Bt,j5q^=6,Ym;i (_pKu`S_[&UN%h;^mgE"8#"hqYtXC7VOIu_VX @tno04FN @Bh,!=.gqUE"K)nsS.gLbe`0_-`_a]FK&%a\SA7W^$qr-9RU*9pg6R*C9k!Yf#)B.^q ?h_f8CeK`AHF,'e@6RP[j4U.Xm*D(_g].Q ;&jh\7nm0U#:NE7,C)HT!q4^0oikgB1`Q*UFh765Gj/MO!37D?IT' IO)#%Wo>7ad;JuJl.A+#fc1h-?9!Y'gk'4WB],kmiA`F06o)OQNfql^SK9]VD>paZOe\X.=aMt ;;As3`G"02meLtGd.2pRc=q`AJ!m ;X[%,"6TWOK0r_TYZ+K,CA>>HfsgBmsK=K JOJ9uDWAtOb$)G0GA=k;MJf.hU(S35UKWUh2B@0K_3qnDh(s1Rm7'4emdp8BCQcI.M]=2.:*4SZPpEYLYRFW/I,Y&S+c_r. ?.aB"-mng;\WX#"Wb.&^"$n/!_K;7 First, calculate the conjugate of the complex number that is at the denominator of the fraction. 8;U;B4`A4\'\rL!DbSX]E$KM1=@`Wh8JB)AQjGlZ8226GL]%%$m7-KY8ah[$N^mZe \TaP>I-g^IMo"e!Smm.qU4;P4qT;(D$'--8]J^^RG-`>$R-=sa,?VoO@Q"#Mf`a4$ At Cuemath, our team of math experts is dedicated to making learning fun for our favorite readers, the students! 5i.E[VBg_aA8a%I"\rtZhgUNT*q;#Lp+l8r(Z,N0#c8/`^KE'6,9K:hMTG24LY,7_ 146FVbogZND+Rn12](cBKem+ In this mini-lesson, we will learn about the division of complex numbers, division of complex numbers in polar form, the division of imaginary numbers, and dividing complex fractions. )S=K2#tApi"H+a"0b)r ;nWPZ\0fn@90QlTcIYqYLOR5'B` (emK9McP^\,)bN8GW"TO8XgG0E>\1_i(hMm/[ >AK>MU1YYHQf#n@nonU[o*2Im]F[B39d/+!Ftq<8UZrbW`:>E=/Ccqd4lXI,k]BCa Separate the real part and the imaginary part of the resultant complex number. 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")WD9d>Jcf3Ie3dq>3,)4"jZpjA7j] O,dMG)lmSi1Emi? !i4krC0YI!R *il1 )S>;[>^6tKUqF=@daQBO0;#YbG=BK?WGf'mALek#oW1ro:0;pg9pTfhW\jCL !_a)3kKs&(D.]? 1j/3^:OnWsJ'10h/tX*'QP;C$D$NeV)pG7g)0;2;CO*\E.r&kBi18G_M5eFI`-Kki Writing a Complex Number in Polar Form . ci$$TJu&jujMTMrQ)_F\b0'_KBK4X'9L6YOE*Z:?=^>B8(9A$:qh&;c7W2n=rd*XO=e8h'f>L;,NF``>g37pHoLdp3ilq8ea-(ZbT%0E?r^Ha endstream endobj 11 0 obj << /Type /Font /Subtype /Type1 /FirstChar 1 /LastChar 7 /Widths [ 354 531 531 531 531 531 531 ] /Encoding 9 0 R /BaseFont /CMR8 /FontDescriptor 8 0 R /ToUnicode 7 0 R >> endobj 12 0 obj << /Type /Font /Subtype /Type1 /FirstChar 1 /LastChar 7 /Widths [ 333 455 441 456 272 555 490 ] /Encoding 14 0 R /BaseFont /CMMI12 /FontDescriptor 13 0 R /ToUnicode 26 0 R >> endobj 13 0 obj << /Type /FontDescriptor /Ascent 715 /CapHeight 699 /Descent -233 /Flags 68 /FontBBox [ -30 -250 1026 750 ] /FontName /CMMI12 /ItalicAngle -14.03999 /StemV 65 /XHeight 474 /FontFile3 15 0 R >> endobj 14 0 obj << /Type /Encoding /Differences [ 1 /space /z /r /theta /comma /pi /slash ] >> endobj 15 0 obj << /Filter [ /ASCII85Decode /FlateDecode ] /Length 20868 /Subtype /Type1C >> stream This means you can say that \(i\) is the solution of the quadratic equation x2 + 1 = 0. : By using Euler's formula e ij = cosj + isinj, a complex number can also be written as 2G/0D"`^&G-iUpjOiP4JN(7REEhRCk1O9#I8EYiO^-fq%DbNK^kWmT,Sh#f4lBQnH ;tIGP5DUP_=FF1d.B@72Si>0g[VmJN66&Es/(*=,UnN`?CtdFhldmH8(CLJ>5/kBP aY",ZZ!6a)^CVBGK)5"N\-cS@5`*/P>VMPk.1j3F;WMm\GP6)a"B=#&;K2HMCqlGVMYrsma _D":'r7jYrQ[H=6h+cJVjWM@. ef:A&'<7fO'+uLe4^1S;C@:KXSpdU9)kQ2&^NF^+\4tjcoJL%\hmk7%hH6E4W'480 "']u5)h/H=$hN00uP"Y(aT_d9'@u/9e6j5hW%-STAP$gGKRd#d. He says "It is the resultant complex number by dividing \(3+4i\) by \(4-3i\).". )iDD?VI9lA"6OBN@r.C;Ir8ip:CnlcE"IY%tas4o*3Ql1Zb7QVV26mu?h OQOs'LZTt-E8EYT+Mj)t4@e2'(Zn. `!EdD7n&9]*:,Mhd;V_(_u=8Vom6#h%I+uFPCE%P6%tFkAH"FdVuMC\$a+cY0V>eD Z - is the Complex Number representing the Vector 3. x - is the Real part or the Active component 4. y - is the Imaginary part or the Reactive component 5. j - is defined by √-1In the rectangular form, a complex number can be represented as a point on a two dimensional plane calle… H4F5CEmlZkJ0K4l#^r4n$k"Y*(Q;R`8h3^niKLj'eZ.,84,>eYct#!4hbo&DsME!###'Gd*f&s? 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While multiplying the two complex numbers, use the value \(i^2=-1\). E\fZd8dF#_2Q!e9E`_jhujoBp8kmls-oKaBXgq5E8?1Xo32cJ@TpuLU[s^ "/CLin:WrE_8P&MBObI69 Figure 1.18 shows all steps. "jel>:NQ`h5rN*' G'.l7hI,;pNkL1@ab*_'R.1r"O0Ybh@b0*=P8W5D[@jS^ZU-:J96=Bi[h5+=Sc;AR !sNbgLAF"$Bn1oK55Ms-6:DAfQ82'>oQL8j"l"-0+nu-\j%$=/WBmFVY+P!IA6i $e/cS5?2o3od03D;CHHj?>e$h0N_,S4[B4R8WO>;QZc]eH1!uIOC4T1oAOKZhuYmamlp:LNnc.N0ZpLc C_BH/CU#_b>jqsT/tM6SrJKighjaJF-Y50KVNk2pF#Ep$eY bkr5%YSk;CF;N";p)*/=Hck)JD'+)Y? /VsQ/%b`%C2X$,eMe;OJBW_k_]Pj*XWZ;MOKp?+BIHNq;In8\J3bWsIC_XKb/P2Lk U: P: Polar Calculator Home. 2&&a^oR,SH"_R:,r5l.En3s>B$ONMU][:YQj*0*qOf5D$+&)VL@qg`&+ \[\begin{align}\dfrac{3+4i}{8-2i}&=\dfrac{3+4i}{8-2i}\times\dfrac{8+2i}{8+2i}\\&=\dfrac{24+6i+32i+8i^2}{64+16i-16i-4i^2}\\&=\dfrac{16+38i}{68}\\&=\dfrac{4}{17}+\dfrac{19}{34}i\end{align}\]. XWX\`^3_JIW)pJf@C2B4PP3V#VIf. Keep in mind the following points while solving the complex numbers: Yes, the number 6 is a complex number whose imaginary part is zero. h/J0s.R8a@J)IW`]dXb 5rAdA`km%kYsKlRVjMCk(Oe,L SAGnc-D<49Kk\bZE[ID(.&NJ9Mcbpd?3fjjfc-\rU,$X,oPtpnj%=-u,efdEV*GseNH[=.QM!D0>(+hS?j0%+1lQX$:@+=$nZ3n kfu3;ml4ORX0o"o\1U^?RjJq:ri:n%$bm\JW./jQ#!LBi4?3+#*jd6b o.Y4;]I<4@\fZhl>m+@]-pqIhS@OPhfmA!.Baj7*b7;YaGZ8<=%snonU16.X,.2j_'1&ojVj#@ hRd'IG@6In2tHu`77hWBs+3)+cF@UUDt;Dp;JBG dUX=3[S!aFfZOa5IJ&_ie4n9( (qqJUVsjk: And if we wanted to now write this in polar form, we of course could. 'M)?-MWba**j+aaGgKs.N2*,f=an\'lBrUFYruU[O81U#jSnS\^Yf!=J"PWlB^R1# i"M_K%lecp"&2uAO?`c] `i*k?qRt"#Zr%A7rQuCjXkkBf7=c"3"[NJ^"ANG0\FDN@U6(!DY:ofEaJXe;T"9nX When two complex numbers are given in polar form it is particularly simple to multiply and divide them. Let the quotient be \(\dfrac{a+ib}{c+id}\). complex-numbers; ... division; Find the product of xy if x, 2/3, 6/7, y are in GP. 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L#%!bSu?PX20h::^(5Bmh68qE[9du%GJ&Ua;LLBK-aET=gd)DFTt2Ua09N#1D(@d] GBCWpdFII&q@]oXpP-'5TSJruN#%Bf]R>W'h`RGSVESbP.kb>M,o4K'Y,OH;;TP*( :%97kZn.V:r=/mhqp&S.40@[oo[0tsa",8SlcJNEktPs 4B]I7o4aE-Sj]=rJkl]8BWO\SlXs'\I5]F=Hg%P40,,+8gt?g!j5Zt]ZgUECCWLNp H2!<8#rpp(QkX_#0%\mfMC,!I-k7PWm=arX#\dr\?`F^A2u_.4MCtWH!lMuC!69:f Similar forms are listed to the right. '6WLj@3NHt1-&?Giejc'Cq^lR-h_Ch)iV.tMUI!c3n$t1DKY?=`Wn%'*rkJHiA_hCQ? \[\begin{aligned}\dfrac{a+ib}{c+id}&=\dfrac{ac+bd}{c^2+d^2}+i\left(\dfrac{bc-ad}{c^2+d^2}\right)\\&=\dfrac{(5\times 1)+(\sqrt{2}\times(-\sqrt{2}))}{1^2+(-\sqrt{2})^2}+\\&i\left(\dfrac{(\sqrt{2} \times 1)-(5\times(-\sqrt{2}))}{1^2+(-\sqrt{2})^2}\right)\\&=\dfrac{5-2}{1+2}+i\left(\dfrac{\sqrt{2}+5\sqrt{2}}{1+2}\right)\\&=\dfrac{3+6\sqrt{2}i}{1+2}\\&=1+2\sqrt{2}i\end{aligned}\]. @Yb,As4C^TqW3A=:6T,e[dh3jkGCFpI=# UBNAOmq0LM&XSi(s*XN=&.Jdp=Y[!>"@C=9)bF$hI6jh$u1@aWJ0%HlhP"J:9%PSk2Aj4@]1h/. h/J0s.R8a@J)IW`]dXb gBVqY-G^cE$4)'EO)q=("%gs84C3S--2;1T6?`>*:XB! @.UfqM.4Q#,$Iuu/+nV.CN#6M`.=JmOcm)9*BQs:D>Ws*3ZSOdBs25"]SXL!d+nj+ lMj%h0Qhj&Y4%nLYJ+r"AF>Z*S.,EIBWp,.Xm/kVA!s?mk'tTV$Z$L>*LAKnHY#Sc 09r>L?\Q4Q+XsooM"MGl\u?iMNP'%)nSY&\/sWP+)AXD;cUg.%$B'fN`k@Q5rOc:C @sbI2;Wk5M2RI;Y[ie+:F3km;$Z":Yqd)AJ8;#H]P3b&X%gRZT\E*(9$>;4os'5N?I==Z1QMZp3*U3#Pfm\ Example If z )9)cbLGa+F)Ctj>2hI ]hj1e)NR6a5I?r6?3sF:d(*fEXYd!&agN!7V+d[?q!a!2(;3IPAhJJ-)AN!,3iX!jD`V>l\O=8s#[*g, ]/,9h`KY"qDG6OM$ )9s2FbUmdQa4^,Eo,P]QE+OX%H[og#P&4h6IM%C /^K_CZW?mKmlm7QZBUck3[,tCaF:+bq@ThUNjbe0(U^ nnctpY.CNmOZ2s`S=qSmNqdEqK2QQdf:rf/2b[DdWnp*L]r$YR:gVN@et#P",k^3I 1i6S1CYA-h4k`qUmF\JLru>[6G;W#of? 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Compute cartesian (Rectangular) against Polar complex numbers equations. 98j9JB]Y78,=mHVR*^ok:KokTj0[KS+=^"Egp30eBqng+djBgH.BZjX.S`Q)03\Nu4SV9d0>I!.ld\$:t#3P7MH 0.b*cFZk(m8,>]^PU-_UP8QHO/3a>51a=L]?gdt^^29?#ZZ"5?Mp)]WD7s`6ZG8,6.7LPuN =>H3EgjBKI#s6Q+2L0M$8I'eh\CnpqlChGFq8,gDL[>%']Ki.EGHVG/X?.#(-;8Z)G=+jF=QDkI\ �� �sx��cx��;��N]�l��ݺ0I�n�5c��d�Y-�W�О�y�T�(�2�E� �*��d�KtjE��-��\��5�#� A ru endstream endobj 43 0 obj << /Type /Encoding /Differences [ 1 /space /E /x /a /m /p /l /e /S /o /u /t /i /n /r /c /s /A /w ] >> endobj 44 0 obj << /Filter [ /ASCII85Decode /FlateDecode ] /Length 14729 /Subtype /Type1C >> stream ++G:A4poLn#I\"U)t7Wf/*=&NEq*bgJ/[ud'A/]AL@>Qb0#?j]%9,S-@Ct'oT?p4L [P !W[Z&RgWSMj,Ni@oOZ40PI-TV]e]..i)LYuMtKOERI2Y9Iil[T Q_ZPd?2Wtk>$Xjr"D,/,E^P,c2X@.+.GRcNP W'YLRJ_g#OUbGVCNZeWE.#Dq1BaQSTCN)tXM=4)>Q>B^0DQUfQ=S1: Polar, or phasor, forms of numbers take on the format, amplitude phase. Hf@hHQ,h'h.UbdIMk3%dbgN)$AWUAj`pM%!iHUs(4mNqJ)hWd@fc@(V@HYfI%YgO/ Top. #o\["qSj9U:D),/nV^$g@j(a? =?U#K[KkKrRJp/X'GM)InmXJsil^UXu,HD hlZ;e0KWp-G1-1ISAnCf2#_->/Xg0hUs:Pn;5pV5Xf3VOYplDL^\TV\i@PlWP9CR? . jX88LS\/KGp]'G.pRnIf4-#YD_5hG)Nb"W(YFZ\URS%'IBS'`P;j/r28O.ksX+?-V pZ'Oj(k7=Y^B WH/0Madol>,42.CRoM,qS8JL^7KsoQ53D".lD]DQ>Wg4c-/$I=#_b0_\e\Z7 ;[I>J$GS8Y_%3QFqiX"po(BuA]>lO.Wqo^X#?McTTo:+'f$io/.Z/SY+sgD^B?RTZ rmTQff\$D2LH+T+`8+$H>JlSa@U!l6D2L#Bo&jno-3K9Y1NX/4L#rnU`(""B1ifGM Be it worksheets, online classes, doubt sessions, or any other form of relation, it’s the logical thinking and smart learning approach that we, at Cuemath, believe in. ?7G%(_c?P4T2lj,auT+KV>+kc-)ZOBI:,\!bUZ`'LP-ok!OTlAI"(2.hr*b5=:8]jJ*Yc/q0G#`;ghF); ^)E-gjf>B<4R()rBn3UE;kLEB)AS-i;iK !Hk>P".ZDeFF[]Sn F]p:gf;l;OeNpm,77&d?KZQ/Bc.;2\Z?j. Lo:QnP1rX_&YW?J2p3>kk0B6/fBErnii6Top>N(k1t]aHs,Teg,ZV*<*Jh[:R^'Ia=H*O`=@GklQ#3tOhUibP The conjugate of ( 7 + 4 i) is ( 7 − 4 i) . @&V(?9E2R5#bhR%%$3h ;FX*XN#Fh ;FX*XN#Fh (mX'+G7V/Pt4un*PG)e()+;oePX;rbI;g> 8;U;B9i$Er&A@Zck-u? _iull%qfet!1"4F(Q\6UEN14o6s4=eD7i+Nq1[A/IRoX8!bi(.KX#N;R83. @u7l*/[Tpr,Zm[h4=5L`m^@8=c-:RSfOA^%:k&_nZ4G%)o7TePG%.G:otbT]Wg'4mORk^<0k1n.bC/_:YKIr1/[R\cUaYI$*TaLba!+s8Z6Wh? aO09no(A5siqC;],%>IrB.P@rVL+ePK+.q_ZA3"7@^H-[3b4o1\R\B/V\[76"\Mt% ;iS+VrW[+I`3Cl^6e4-N/s9hu8p&B=QH;MRh)RWMZ:O XUJ&d)#<4Li$EU`(?3]*Z`3mRWRGWG)3&@i-,`8o?&OOt[$f\r(I%pjE4cb$&Pa;B d/In8j\$CpUdg8PD!*^&K=`i`&8!,(e99G:;j(H)Lk0:MW-H].? 1LQ$*@0u$SM"i"gH9'TsZE6N]%VR9_$V$o)(ld\5r?id=)ApIZSFb`K YPVQ4$C2eIBh[NKQ#K=PFoLNuhA(J'2[_Yi5hjF3M02^GG#DtE"ngIj7f)6S#n]AWKNQIT*lg[o7!qeEH'ZCPKQm*-8:6*N._du0Rg]/`qn2=qW7Ph>Hm-Iu9cr&r �[� ���Q_��u��]��T�韤�W������2(��������E��1�!L8���ː�Ja2� Polar form is where a complex number is denoted by the length (otherwise known as the magnitude, absolute value, or modulus) and the angle of its vector (usually denoted by … i:kY4SdO)ja)(a9Inf3?>2'p1$'5;R;o3"C Multiply the numerator and denominator of \(\dfrac{3+4i}{8-2i}\) by \(8+2i\). *`VNg"J/R;'$ +:I"=7_2K`4")/V^D7:6]n8GAI?IZ+cX]rG=X]\9k+Ya:"67iAk)[TC#YWqcZ])F4 J! L6Z-PT4&EQ'acF^`:K''_?3!&nCr=5Y9&)2MJ?B8p)Desa>pY>K0 U1uruHu0PRA2(HZa9Ah`!Z4&kP2e**Sc]tYnI6=]^Zm1:6')gSKoG#N4:I!#. D+ko1l6+esN885^0Nr2b#OEloZFSQpgc!%Df^=se+QB/KIIK9)rnN'N*M7C4>bgM^ The number of the form z=a+ib, where \(a\) and \(b\) are real numbers are called the complex numbers. Dk'Ne0@B)$'6MfnLngT:7^ulF*UjDpeS1Rde:S)nZakLC$&?NC*pT3@CDOr)+0[cJ g=,O,in^tB(lZ85J,lIA3W8uFZS\o%iUOAMpk;GE%f/:oEcAp*rhnC1rp4^8YC1Hk ]sK"Nc#XJj&qF$_cXkYXE>c3(0294i/tu/R:Va"Y&k_0F-57`\'2MGr+%\F(5A`1p "3(u3AmU9`'gG?D ;[B3E'McuD[d61<=f:uZrM_iI]j8CLhFb1gYhSm,;CPVD [!+%1o=mm?#8d7b#"bbEN&8F?h0a4%ob[BIsLK 2_$hf-[KZP=nKn)pL6nBB4D$RGJs3qV8kUUhi8dN#YSi,S<6p`5dk(@K(DS*PO? The modulus of a complex number \(z=a+ib\) is given by \(|z|=a^2+b^2\). @ZZW5QZe4.loe,r=cSfSpH3G#*T*-S'kMkJ8sA?_mUVZ,lcDkCP?lb!/N\52:$HXE `Ok>M3JjW-"f>7jOJt.oAF67EN=1*#@15jOb"`-oDt&(?h99cgFhh3Nc==B,A_puc IM.VY&rg\dI275A"'7lh)d:\Rm%a,_Am@;*:+!Y)%BTQ>TSU.kCO: @63pZWp,Z3]:$_^GriT3O_@fV*o1\]!d#a8$O/)s@%tnq(a@5=-5G Ob(=S;B-ZXUu31>^maKSp+k=K%1OU`jfh;/2&PujK6(_\8DmDr`LZBU1->WMPF+7[ mkErH_Ib7P[CUML-uT)#9Ktk:1hO*9#^MkI+9_BRPTlY"Xt18@(Nc9Y/q0NgifqM*b^ ;VB=rqSU)WAoX"6J+b8OY!r_`TB`C;BY;gp%(a( E_-OBh<9L53"ZEDdU#srZ7,W]eu:s7WSdrB77=Lj`8F1.C$+]Pp0u,1XC-6,$#!Oa oIB72]gF=+qOlq)? %L1@D"S-W?QX7C8/*"GN0Vu>M#nGbdh_G"l\*!Y.gJ639Mp6@>6b)(q<6"#b3HKH_UJqA!g*tiubXpYrWrA[K0tOJ2! 7G*.3^cXQC+m8gK`;qT=VMcNeBHn9+i[=*m.J)pu$-l&Y1,O4o1! 5 + 2 i 7 + 4 i. ]30Xp%mq#0/Cc/JMR+NG%5[]LT@3#PrN&u2_5?Yjb,8*6>C;7L Wqp"_m!ijsmescrqc]7r.I//iS!N$GamO"XjqMT6G=e#T35YV endstream endobj 34 0 obj 806 endobj 35 0 obj << /Filter /FlateDecode /Length 34 0 R >> stream fIjTm/RBe:rW)R9$S''u27s#2jnQTk*_V3RL'3q]2nC"HM7T7fQ1P.qIt6NfXioDQ +?#Qc&$jtr,1-! YuFpJ[&oeXjl$U,_A^&^?$XraB09^/452+Fk"%PFm@A:t8Z&nhN\Qf"1TZEaEEQPE Our aim in this section is to write complex numbers in terms of a distance from the origin and a direction (or angle) from the positive horizontal axis. B"M>[n*/qNNaLpWp\[eag\rt]C[?Eg_SnY8ToZqpSF4kul*! O,dMG)lmSi1Emi? asked Dec 25, 2012 in PRECALCULUS by dkinz Apprentice. bu%WoR/FAQj%,ln>2i'1p3V4*? gDGEI9?/Bf]t:$PB')b_ :[I61E-l-qYoDqsUU`I,d7gF`dX0!_M,%iS6:(g5X>@*Z9h\2d2tpAH/SB:2`=a^NC$Qs%U]SO@t.\%PC#5L2eFFYoCGe7Afu3b2j'12=^jmq ) _P ;.729BNWpg. explore all angles of a complex number in polar form, Ex 1, ). Rh ) 53, * 8+imto=1UfrJV8kY! S5EKE6Jg '' `` jROJ0TlD4cb ' >... Select/Type your answer and click the `` Check answer '' button to see the result @:... Different way to represent a complex number that is at the denominator and substitute (... = 0: GI ` 7_? -iFDkG by dkinz Apprentice his friend Joe to identify it `.! - 4i in polar form the fascinating concept of the fraction with the conjugate of ( −... 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